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16.14 In the two-mesh network of Fig. 16-13, nd the currents which result when the switch is closed.

deferred until run time. The rule that the pointer s statically defined type determines which member function gets invoked is overruled by declaring the member function virtual. Here is a more realistic example: .

The time-domain equations for the network are 10i1 0:02 di1 di 0:02 2 100 dt dt di2 di1 0:02 5i2 0:02 0 dt dt

Here is a Person class with a Student class Person { public: Person(char*

page_143

34

subclass and a Professor subclass:

Taking the Laplace transform of set (34), 10 0:02s I1 s 0:02sI2 s 100=s From the second equation in set (35) we nd I2 s I1 s s s 250 36 5 0:02s I2 s 0:02sI1 s 0 35

s) { name = new char[strlen(s+l)];

which when substituted into the rst equation gives s 250 10 3:33 I1 s 6:67 s s 166:7 s s 166:7 Inverting (37), i1 10 3:33e 166:7t Finally, substitute (37) into (36) and obtain 1 I2 s 6:67 s 166:7 A

strcpy(name, s);

37

void print0 protected: char* name; >;

{ tout << "My name is ' CC name << ".\n"; }

The initial value of i1 is given by s 250 i1 0 lim sI1 s lim 6:667 6:67 A s!1 s!1 s 166:7

page_144

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class Student : public Person { public: Student(char* s, float g) : Person(s), gpa(g) { } void print0 { tout << "My name is ' << name << ' and my G.P.A. is ' << gpa CC ".\n"; } private: float gpa; >; class Professor : public Person { public: Professor(char* s, int n) : Person(s), pubis(n) { } void print0 { tout CC "My name is ' CC name << ' and I have ' << publs << ' publications.\n"; private: int publs; >; main0 -t Person* p; Person x("Bob") ; p = &Lx; p->print(); Student y("Tom", 3.47); P = &y; p->print(); Professor z("Ann", 7); p = &z; p->print();

CHAP. 16]

always The print ( ) function defined in the base class is not virtual. So the call p->print ( ) :print ( ) because p has type Person*. The pointer invokes that same base class function Person : p is statically bound to that base class function at compile time. Now change the base class function Person : :print ( ) into a virtual function, and run the same program:

and the nal value is s 250 i1 1 lim sI1 s lim 6:67 10 A s!0 s!0 s 166:7 The initial value of i2 is given by i2 0 lim sI2 s lim 6:667

class Person { public: Person(char*

s!1 s!1

char[strlen(s+l)];

s 6:67 A s 166:7

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